处于n=2能级的氢原子从外部吸收波长为4 848.5 的光子后跃迁到某一激

处于n=2能级的氢原子从外部吸收波长为4 848.5 的光子后跃迁到某一激发态,试求:

(1)吸收的能量为多少电子伏?使氢原子跃迁到哪一激发态?

(2)从该激发态向较低能级跃迁时释放的光子的最低频率为多少?

答案

(1)2.55 eV,4  (2)1.59×1014 Hz


解析:

(1)光子的能量

E=hν=h=6.63×10-34× eV=2.55 eV,2.55 eV恰好是E4-E2,所以氢原子从n=2能级跃迁到n=4能级.

(2)最小频率为ν==1.59×1014 Hz.

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