下列不等式中0<a<1,0<b<1,a≠b,其中错误的是A.0.30.9<log0.30.3    

下列不等式中0<a<1,0<b<1,a≠b,其中错误的是

A.0.30.9<log0.30.3                               B.log0.90.3>0.90.9

C.|loga(1-a)|<|loga(1+a)|                          D.aabb>abba

答案

解析:

0.30.9<1=log0.30.3,∴A正确;

y=log0.9x与y=0.9x互为反函数,关于y=x对称,由示意图知log0.90.3>0.90.9,

∴B正确;

∵0<a<1,

∴0<1-a<1,1+a>1,0<1-a2<1.

∴loga(1-a)>0,loga(1+a)<0.

若|loga(1-a)|<|loga(1+a)|,

则loga(1-a)<-loga(1+a),

loga(1-a)+loga(1+a)=loga(1-a2)<0,显然错误,∴C不正确.

若aabb>abba,则>1,

∵0<a<1,0<b<1,a≠b,

>1,a-b>0或<1,a-b<0,

()a-b>1成立,即D成立.故选C.

答案:

C

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