铝密度是2.7×103kg／m3，现有一块体积为25 cm3的铝块，它受到的重力是

铝密度是2.7×10³kg／m³，现有一块体积为25 cm³的铝块，它受到的重力是多少?

答案

解析：物体重力G＝mg

得：G＝2.7×10³kg／m³×25×10^－6m3×10 N／kg＝0.675 N．

答案：0.675 N

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铝密度是2.7×103kg／m3，现有一块体积为25 cm3的铝块，它受到的重力是

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