(1); (2)
;
(3)(n∈N*,且n>1);
(4); (5)
;
(6)+
+
.
(1); (2)
;
(3)(n∈N*,且n>1);
(4); (5)
;
(6)+
+
.
思路分析:的意义是n为奇数时,a∈R;n为偶数时,a≥0.n为奇数时,
=a;n为偶数时,
=|a|=
解:(1)=
=3.
(2)=
=-3.
(3)=
(4)=
=
.
(5)=|a-3|=
(6)+
+
=-2+π-2+2-π=-2.