p{font-size:10.5pt;line-height:150%;margin:0;padding:0;}td{font-size:10.5pt;}(08杭州五

(08杭州五校月考)某无色溶液,由Na+Ag+Ba2+Al3+AlO2-MnO4-CO32-SO42-中的若干种组成。取该溶液进行如下实验:

A)取试液适量,加入过量稀盐酸,有气体生成,得到溶液甲;

B)向溶液甲中再加入过量碳酸氢铵溶液,有气体生成,析出白色沉淀乙,得到溶液丙;

C)向溶液丙中加入过量Ba(OH)2溶液,有气体生成,析出白色沉淀丁。

根据上述实验回答下列问题:

1)溶液中一定不存在的离子是                (全对才给分)

2)一定存在的离子是                       (全对才给分)

3)生成沉淀乙的离子反应方程式是             

4)写出步骤(C)中一定会发生反应的离子方程式                            

答案

答案:(1   Al3+  Ba2+  Ag+  MnO4-           ( 2 )      (全对才给分)

     (2     Na+   AlO2-     CO32-             ( 2 )      (全对才给分)

     (3  Al3+ + 3HCO3- = Al(OH)3+ 3CO2      ( 3 ) 

     (4 2OH-+ Ba2+ +NH4+ +   HCO3- = BaCO3 +NH3 + H2O     ( 3 )

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