直线l经过点P(﹣3,4)且与圆x2+y2=25相切,则直线l的方程是( ) A

直线l经过点P(﹣34)且与圆x2+y2=25相切,则直线l的方程是(  )

Ay4=x+3    By4=x+3 Cy+4=x3    Dy+4=x3

答案

B解:显然点(﹣34)在圆x2+y2=25上,

设切线方程的斜率为k,则切线方程为y4=kx+3),即kxy+3k4=0

圆心(00)到直线的距离d==5,解得k=

则切线方程为y4=x+3).

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