A.1或a B.1或aa C.aa D.a
∴loga[(logax)]=logax.∴(logax)[loga(logax)]=logax.设logax=t,则有tlogat=t,即t(logat-1)=0.
∴t=0或logat=1.∴t=0或t=a.∴logax=0或logax=a.∴x=1或x=aa.经检验x=1不合题意舍去,故x=aa.故选C.
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