设f、g都是由A到A的映射,其对应法则(从上到下)如下表:表1    映射f

fg都是由AA的映射,其对应法则(从上到下)如下表:

表1    映射f的对应法则

原象

1

2

3

2

3

1

表2    映射g的对应法则

原象

1

2

3

2

1

3

fg(1)]=         ,gf(2)]=         ,f{gf(3)]}=         .

 

答案

333

解析:f[g(1)]=f(2)=3,g[f(2)]=g(3)=3,f{g[f(3)]}=f[g(1)]=f(2)=3.

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