f(x)是以5为周期的奇函数,f(-3)=4,且cosα=,则f(4cos2α)=____________.

f(x)是以5为周期的奇函数,f(-3)=4,且cosα=,则f(4cos2α)=____________.

答案

解析:f(4cos2α)=f[4(2cos2α-1)]=f[4×2×()2-4]=f(-2)=f(-5+3)=f(3)=-f(-3)=-4.

答案

:-4

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