2(t－1)2＋t＝1；

2(t－1)²＋t＝1；

答案

2(t－1)²＋(t－1)＝0.(t－1)(2t－1)＝0.t－1＝0，或2t－1＝0.
∴t₁＝1，t₂＝.

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2(t－1)2＋t＝1；

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