若函数y=log3(+4)在[0,+∞)上单调递增,则实数m的取值范围是A.[1,+∞) 

若函数y=log3(+4)在[0,+∞)上单调递增,则实数m的取值范围是

A.[1,+∞)             B.[0,4)              C.(-∞,1)                D.(1,+∞)

答案

答案:D

解析:

令g(x)=+4.

由复合函数的单调性知,要使y=log3(+4)在[0,+∞)上单调递增需g(x)=+4在[0,+∞)上单调递增,∴m-1>0.∴m>1.

又m-1>0时,+4>0在[0,+∞)上恒成立,∴m>1.

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