如图所示,小明正在做俯卧撑,把他的身体看作一个杠杆,O为支点

如图所示,小明正在做俯卧撑,把他的身体看作一个杠杆,O为支点,A为重心,他的体重为550N.地面对手的支持力F的力臂是   m,大小为    N

答案

1)根据图示可知,支点到重力作用线的垂线段和支持力作用线的垂线段分别为动力臂和阻力臂,即动力臂L1=0.9m+0.6m=1.5mL2=0.9m

2)根据杠杆平衡的条件可得:

FL1=GL2

F×1.5m=550N×0.9m

F=330N

故答案为:1.5330

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