A.y1y2≤x1x2 B.y1y2≥x1x2 C.y1y2>x1x2 D.y1y2<x1x2
解析:y1y2=(ax1+bx2)(bx1+ax2)
=abx12+abx22+x1x2(a2+b2)
≥2abx1x2+x1x2(a2+b2)
=x1x2(a+b)2=x1x2.
故选B.
答案:B