已知点O为△ABC外接圆的圆心,且++=0,则△ABC的内角A等于( A ).
A.30° B.60° C.90° D.120°
A解析:如图,∵++=0,∴+=,
∴四边形OACB为菱形,∴OG⊥AB,∴∠CAB=30°. 答案 A