如图,在△ABC中,AD⊥BC,△ABD的面积是△ACD面积的2倍,沿AD将△ABD

如图,在△ABC中,AD⊥BC,△ABD的面积是△ACD面积的2倍,沿AD将△ABD翻折,使翻折后BC⊥平面ACD,此时二面角B—AD—C的大小为__________.

答案

答案:

60°  【解析】由已知,BD=2ED.翻折后,在Rt△BCD中,∠BDC=60°,而AD⊥BD,CD⊥AD,故∠BDC是二面角B-AD-C的平面角,其大小为60°.

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