用惰性电极电解50ml锰酸钾溶液:K2MnO4+H2O KMnO4 +H2↑+ KOH(未配平)当

用惰性电极电解50ml锰酸钾溶液:K2MnO4+H2O KMnO4 +H2+ KOH(未配平)当生成112ml氢气(标准状况)时停止通电。下列判断正确的是       

AK+浓度减小                    BKMnO4在阳极区生成

C.阴极周围溶液的pH值减小        D.反应过程中共转移0.005mol电子

答案

B

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