(16分)有机物A为绿色荧光蛋白在一定条件下水解的最终产物之一,

(16分)

有机物A为绿色荧光蛋白在一定条件下水解的最终产物之一,结构简式为:

请回答下列问题:

(1)A的分子式为                        。

(2)A与氢氧化钠溶液反应的化学方程式为                                            。

 

 

 

(3)已知:

两个A分子在一定条件下生成的化合物结构简式为                                   。

(4)符合下列4个条件的同分异构体有6种,写出其中三种                          。

①1,3,5-三取代苯

②遇氯化铁溶液发生显色反应

③氨基与苯环直接相连

④属于酯类

 

答案

(16分)

(1)C9H11NO3           (2分)

(2)

                                                                 (4分)

 

(3) (4分)

(4)(各2分,6分)

(书写方法可以从分类的角度思考:芳香酸和脂肪醇形成的酯、芳香醇和脂肪酸形成的酯、酚和脂肪酸形成的酯,再考虑碳链异构现象。)

解析:

 

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