如图11所示电路中,电源电压保持不变,R1=6Ω, R2=12Ω,求:(1)闭合

如图11所示电路中,电源电压保持不变,R1=6Ω, R212Ω,求:

(1)闭合S1,断开S2,电压表示数为3V,则电源电压为多大?

(2)闭合S2,断开S1,电压表示数为6V,小灯泡恰好正常发光,则小灯泡的额定功率为多大?            图11

答案

1)通过R1的电流:I10.5A

R2两端的电压U2I1R20.5A×12Ω6V

电源电压UU1U23V6V9V 

2)此时LR2串联,R2两端的电压:U2′=UU1′=9V6V3V

通过R2的电流I20.25A

小灯泡的额定功率PLU1I26V×0.25A1.5W

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