解析: A={-2,4},∵BA,∴B=,{-2},{4},{-2,4}
若B=,则a2-4(a2-12)<0,a2>16,a>4或a<-4
若B={-2},则(-2)2-2a+a2-12=0且Δ=a2-4(a2-12)=0,解得a=4.
若B={4},则42+4a+a2-12=0且Δ=a2-4(a2-12)=0,此时a无解;
若B={-2,4},则
∴a=-2
综上知,所求实数a的集合为{a|a<-4或a=-2或a≥4}.