如图,将充满CO2的试管倒扣在滴有紫色石蕊的蒸馏水中,一段时间后

如图,将充满CO2的试管倒扣在滴有紫色石蕊的蒸馏水中,一段时间后,下列实验现象描述正确的是(  )

试管内液面上升试管内溶液变红

试管内液面不上升试管内溶液变蓝试管内溶液不变色.

A①② B①④ C②③ D③⑤

答案

【分析】二氧化碳能与水反应生成碳酸,呈酸性,因此能使紫色石蕊试液变红.

【解答】解:二氧化碳能溶于水的,并且与水反应,大试管内气体减少,压强变小,烧杯中水面上升故正确.二氧化碳与水反应生成碳酸,呈酸性,能使紫色石蕊变红,故而试管内的液体变红.故正确.

故选:A

 

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