如图18-1-6所示的LC振荡电路中,某时刻线圈中磁场方向向上,且电路

如图18-1-6所示的LC振荡电路中,某时刻线圈中磁场方向向上,且电路的电流正在增强则此时(    )

图18-1-6

A.a点电势比b点低                        B.电容器两极板间场强正在减小

C.电路中电场能正在增大                    D.线圈中感应电动势正在减小

答案

ABD


解析:

因为电路中电流正在增强,所以电容器处于放电过程中,极板上的电荷不断减少,两板间的场强正不断减小,电场能也不断减小,由安培定则可判断得此时电容器放电的电流方向由b经线圈到a,电容器的下板带正电,上板带负电,所以b点电势高于a点电势,电流增大时,电流的变化率(磁通量的变化率)减小,所以线圈中的自感电动势在减小,A、B、D正确.

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