说出由曲线y=tanx得到曲线y=3tan2x的变换规律,并求满足其图形变换的伸

说出由曲线y=tanx得到曲线y=3tan2x的变换规律,并求满足其图形变换的伸缩变换.

答案

思路分析:

函数y=f(ωx),x∈R(其中ω>0,ω≠1)的图象,可以看作把f(x)图象上所有点的横坐标缩短(当ω>1时)或伸长(当0<ω<1时)到原来的(纵坐标不变)而得到.

函数y=Af(x),x∈R

(其中A>0,ω≠1)的图象,可以看作把f(x)图象上所有点的纵坐标伸长(当A>1时)或缩短(当0<A<1时)到原来的A倍(横坐标不变)而得到.

图形变换的伸缩变换公式:.

解:y=tanx的纵坐标不变,横坐标缩短为原来的,得到y=tan2x,再将其纵坐标伸长为原来的3倍,横坐标不变,得到曲线y=3tan2x.

设y′=3tan2x′,变换为将其代入y′=3tan2x′,得μy=3tan2λx.与y=tanx比较,可得

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