已知25℃、101 kPa条件下:  4Al(s)+3O2(g)===2Al2O3(s)ΔH=-2834.9 kJ/mol 4A

已知25℃101 kPa条件下:  4Al(s)3O2(g)===2Al2O3(s)ΔH=-2834.9 kJ/mol 

4Al(s)2O3(g)===2Al2O3(s)ΔH=-3119.1 kJ/mol由此得出的正确结论是     (  )                                  

A.等质量的O2O3能量低,由O2O3为放热反应

B.等质量的O2O3能量高,由O2O3为吸热反应

CO3O2稳定,由O2O3为放热反应    

    DO2O3稳定,由O2O3为吸热反应

答案

D

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