如图,四边形ABCD为直角梯形,AD‖BC ,,,.动点P、Q分别从A、C两

如图,四边形ABCD为直角梯形ADBC 动点PQ分别从AC两点同时出发,点P以每秒1个单位的速度由AD运动,点Q以每秒2个单位的速度由CB运动,当点Q停止运动时,点P也停止运动,设运动时间为0≤≤5),

1)当t为多少时,四边形PQCD是平行四边形?

2)当t为多少时,四边形PQCD是等腰梯形?

]

答案

解:(1)设t秒后,四边形PQCD是平行四边形

              

答:2秒后四边形PQCD是平行四边形.

    (2) t秒后,四边形PQCD是等腰梯形

     

 


答:秒后四边形PQCD是等腰梯形.

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