若f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f'(1)等于A.0

fx)=(x-1)(x-2)(x-3)(x-4)(x-5),则f'(1)等于

A.0                              B.24                             C.-24                         D.-120

答案

解析: f'x)=(x-1)'x-2)(x-3)(x-4)(x-5)+(x-1)[(x-2)(x-3)(x-4)(x-5)]',

所以f'(1)=(1-2)(1-3)(1-4)(1-5)=24.

答案:B

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