假设有一载人宇宙飞船在距地面高度为4200km 的赤道上空绕地球做匀

假设有一载人宇宙飞船在距地面高度为4200km 的赤道上空绕地球做匀速圆周运动,地球半径约为6400km,地球同步卫星距地面高度为36000km,宇宙飞船和地球同步卫星绕地球同向运动,每当二者相距最近时,宇宙飞船就向同步卫星发射信号,然后再由同步卫星将信号发送到地面接收站,某时刻二者相距最远,从此刻开始,在一昼夜的时间内,接收站共接收到信号的次数为                              (    )

A.4次                B.6次            C.7次            D.8次

 

答案

C

解析:宇宙飞船轨道半径为r1=4200km+6400km=10600km,地球同步卫星轨道半径为r2=36000km+6400km=42400km,r2=4 r1.根据开普勒第三定律,地球同步卫星为宇宙飞船周期的8倍。从二者相距最远时刻开始,在一昼夜的时间内,接收站共接收到信号的次数为7次,选项C正确。

 

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