解:∵A∩{-1,0,1}={0,1},∴0∈A且1∈A.
又A∪{-2,0,2}={-2,0,1,2},∴A中还可以有元素-2或2.
∴适合条件的集合A有四个:{0,1},{0,1,-2},{0,1,2},{0,1,-2,2}.