过氧化氢在二氧化锰作用下分解放出氧气的反应机理如下:      

过氧化氢在二氧化锰作用下分解放出氧气的反应机理如下:

         MnO2 + H2O2 + 2H+      Mn2+ + O2↑ + 2H2O     Mn2+ + H2O2      MnO2 + 2H+

下列说法正确的是

AH2O2中是氧化剂中是还原剂

BMn2+中是还原产物,在中是氧化产物

C.在中每生成1 mol O2,转移的电子数为2.408 × 1024

D.在二氧化锰催化作用下1 mol H2O2分解生成0.5 mol O2

答案

D

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