已知△ABC,延长BC到D,使CD=BC.取AB的中点F,连结FD交AC于点E. (1)

已知△ABC,延长BC到D,使CD=BC.取AB的中点F,连结FD交AC于点E.

(1)求的值;

(2)若AB=18,FB=EC,求AC的长.

 

答案

解:(1)如图,连接FC、AD.

∵点F是AB的中点,CD=BC,

∴FC是△ADB的中位线,

∴FCAD,

∴△EFC∽△EDA,

==2,

=

(2)∵点F是AB的中点,AB=18,FB=EC,

∴EC=AB=9.

由(1)知,=2,则=2,故AE=18,

∴AC=AE+EC=18+9=27.

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