下列结论正确的是 ①粒子半径:K+>Al3+>S2﹣>Cl﹣           

下列结论正确的是

①粒子半径:K+Al3+S2Cl                ②氢化物的稳定性:HFHClH2SPH3SiH4

③离子的还原性:S2ClBrI       ④氧化性:F2Cl2SSe

⑤酸性:H2SO4H3PO4H2CO3HClO      ⑥非金属性:ONPSi

⑦金属性:BeMgCaK

A.①②⑤⑦          B.②③④⑥       C.②④⑤⑥⑦             D.①②⑥⑦

答案

C

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