(12分)根据要求填写:(1)金属钠在空气中燃烧,火焰呈  色,

(12分)根据要求填写:

(1)金属钠在空气中燃烧,火焰呈  色,化学方程式:                       

(2)将过氧化钠固体放入试管中加入少量水,再加入几滴酚酞试液,溶液变红色但很快褪色,原因是:                                     ,过氧化钠固体与水反应的化学方程式:                                              

(3)苏打和小苏打分别和同浓度的盐酸反应,反应较快且剧烈的是       (填化学式),小苏打与盐酸反应的离子方程式为:                                        

(4)金属钠和金属钾分别和水反应试验中,其中反应较剧烈的反应的化学方程式:                                            

 

答案

(12分)

(1)黄(1分),2Na+O2====Na2O2(2分)

(2)过氧化钠有强氧化性(或过氧化钠有漂白性)(2分),2Na2O2+2H2O=4NaOH+O2↑(2分)

(3)NaHCO3(1分),HCO3+H+= H2O+CO2↑(2分)

(4)2K+2H2O=2KOH+H2↑(2分)

解析:略

 

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