下列电离方程式书写正确的是( ) A.CH3COOHCH3COO-+H+ B.Ba(OH)2=

下列电离方程式书写正确的是(  )

ACH3COOHCH3COOH

BBa(OH)2===Ba22OH

CNaHCO3===NaHCO

DH3PO43HPO

答案

解析:选ACH3COOH是弱电解质,电离方程式用”连接,A项正确;Ba(OH)2是强电解质,电离出的阳离子符号为Ba2B项错误;NaHCO3是强电解质,但HCO是原子团,正确写法应是NaHCO3===NaHCOC项错误;H3PO4是弱电解质,应该分步电离,第一步电离为H3PO4HH2POD项错误。

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