如图所示，在Rt⊿ABC中，∠C＝90°，AC＝8，CB＝6，在斜边AB上取中点M,

如图所示，在Rt⊿ABC中，∠C＝90°，AC＝8，CB＝6，在斜边AB上取中点M,过M作MN⊥AB交AC于N，则NC＝。

答案

解析:
：先由勾股定理求出AB的长AB=10，再由相似

∽

求出

，AN=

.NC=AC-AN=8-

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如图所示，在Rt⊿ABC中，∠C＝90°，AC＝8，CB＝6，在斜边AB上取中点M,

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