如图,已知,A(0,4),B(-3,0),C(2,0),D为B点关于AC的对称点,

如图,已知,A0,4),B-3,0),C2,0),DB点关于AC的对称点,反比例函数的图象经过D

1)证明:四边形ABCD为菱形;

2)求此反比例函数的解析式;

3)设过点C和点D的一次函数ykxb求不等式  kxb0的解,(请直接写出答案)

4)已知的图象上一点Ny轴上一点M,且点ABMN组成四边形是平行四边形,求M点的坐标。


答案

解:(1)由勾股定理得,AB=5=BC

DB点关于AC的对称点,

AB=ADCB=CD

AB=AD =CD=CB

∴四边形ABCD为菱形。

2D点的坐标为(5,4),反比例函数的图象经过D点,

,∴k=20,∴反比例函数的解析式为

3  

3)由题意知①N点的横坐标为3,代入,得,

M点的纵坐标为,∴M点的坐标为.

N点的横坐标为-3,代入,得

M点的纵坐标为,∴M点的坐标为.

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