已知点F是抛物线C:的焦点,S是抛物线C在第一象限内的点,且|SF|=.

 已知点F是抛物线C:的焦点,S是抛物线C在第一象限内的点,且|SF|=.

(Ⅰ)求点S的坐标;

(Ⅱ)以S为圆心的动圆与轴分别交于两点A、B,延长SA、SB

分别交抛物线C于M、N两点;

       ①判断直线MN的斜率是否为定值,并说明理由;

       ②延长NM交轴于点E,若|EM|=|NE|,求cos∠MSN的值.    

答案

解:(1)设(>0),由已知得F,则|SF|=

           ∴=1,∴点S的坐标是(1,1)------------------------2分

(2)①设直线SA的方程为

           ∴,∴

           由已知SA=SB,∴直线SB的斜率为,∴

           ∴--------------7分

       ②设E(t,0),∵|EM|=|NE|,∴

,则--------------------------8分

         ∴直线SA的方程为,则,同理

         ∴---------------------------12分

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