解:(1)

,

.

轴于点

.

,

.··································································· (1分)

点

的坐标为

.··················································································· (2分)
设反比例函数的解析式为

.
将点

的坐标代入,得

,

.··········································································································· (3分)

该反比例函数的解析式为

.··································································· (4分)
2

,

.························································································ (5分)

,

,

.························································································ (6分)
设直线

的解析式为

.
将点

的坐标分别代入,得

解得

······································································································· (7分)

直线

的解析式为

. …………(8分)解析:
略