解:cos(105°-α)=cos[180°-(75°+α)]=-cos(75°+α)=--.
sin(α-105°)=-sin(105°-α)=-sin[180°-(75°+α)]=-sin(75°+α).
∵cos(75°+α)=>0,又α为第三象限角,可知角75°+α为第四象限角,
则有sin(75°+α)=
=
∴cos(105°-α)+sin(α-105°)