图甲为某电热水器内部简化电路图,R为电热丝,乙为其铭牌。根据

图甲为某电热水器内部简化电路图,R为电热丝,乙为其铭牌。根据铭牌上的信息,求:

(1)热水器正常工作时通过它的电流;

(2)热水器正常工作50s产生的热量。

 

答案

(1)3A(2)33000J

解析:热水器正常工作时通过它的电流可以用公式I=P/U计算,热水器正常工作50s产生的热量根据Q=W=Pt求出。

解:(1)‍∵P=UI ∴I=P/U=660W/220V=3A————————1分

(2)   Q=W=Pt=660W·50S=33000J—————————1分

 

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