(本题满分16分)已知:椭圆(),过点,的直线倾斜角为,原点到

(本题满分16分)已知:椭圆(),过点,的直线倾斜角为,原点到该直线的距离为.

(1)求椭圆的方程;

(2)斜率大于零的直线过与椭圆交于,两点,若,求直线的方程;

(3)是否存在实数,直线交椭圆于,两点,以为直径的圆过点?若存在,求出的值;若不存在,请说明理由.

答案

(16分)(1)由, ,得,,

所以椭圆方程是:……………………4分

(2)设EF:()代入,得,

设,,由,得.

由,……………………8分

得,,(舍去),(没舍去扣1分)

直线的方程为:即……………………10分

(3)将代入,得(*)

记,,PQ为直径的圆过,则,即,又,,得.………………14分

解得,此时(*)方程,存在,满足题设条件.…………16分

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