












解析:A=“掷出偶数点”={2,4,6},
B=“掷出3的倍数点”={3,6},
∴={1,3,5},
={1,2,4,5},
P(A)==
,P(B)=
=
,P(
)=
,P(
)=
,
A∩B={6},P(A∩B)=,
∩B={3},P(
∩B)=
,A∩
={2,4},P(A∩
)=
,
∩
={1,5},P(
∩
)=
,P(A∩
)=P(A)·P(
),P(A∩B)=P(A)·P(B),P(
∩B)=P(
)·P(B),P(
∩
)=P(
)·P(
).