解析:A=“掷出偶数点”={2,4,6},
B=“掷出3的倍数点”={3,6},
∴={1,3,5},={1,2,4,5},
P(A)==,P(B)==,P()=,P()=,
A∩B={6},P(A∩B)=,∩B={3},P(∩B)=,A∩={2,4},P(A∩)=,∩={1,5},P(∩)=,P(A∩)=P(A)·P(),P(A∩B)=P(A)·P(B),P(∩B)=P()·P(B),P(∩)=P()·P().