将五边形纸片ABCDE按如图10所示方式折叠,折痕为AF,点E、D分别落在E

将五边形纸片ABCDE按如图10所示方式折叠,折痕为AF,点ED分别落在E′D′,已知AFC=76°,则CFD′等于( 

A31°     B28°     C24°      D22°

             

答案

B

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