如图12-7-6所示,实线表示波峰,S为波源,设波源频率为20Hz,且不运

如图12-7-6所示,实线表示波峰,S为波源,设波源频率为20Hz,且不运动,而观察者在1 s内由B运动到A,观察者接收到多少个完全波?设波速为340 m/s,若要让观察者完全接收不到波,那么,他的运动速度应该是多少?

图12-7-6

答案

21


解析:

(1)观察者在单位时间内接收到的完全波的个数,即接收到的频率.如果观察者不运动,在1 s内,观察者接收到的完全波的个数应当是20个,然而当观察者从B运动到A的过程中,所能接收到的完全波的个数正好比不运动时少1个,即他只能接收到19个完全波.(2)要想让观察者完全接收不到波,他必须远离波并随同所在的波峰一起运动,即观察者的运动速度应该是340 m/s.

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