图2-4-4
思路解析
解
∴∠BAE=∠C.
∵AE平分∠CAB,
∴∠BAC=2∠BAE.
又∵∠C+∠BAC =90°,
∴∠BAE =∠C =30°.
则有BE =1,AB =,BC =3,AC =2.