二次不等式ax2+bx+1>0的解集为{x|﹣1<x<},则ab的值为( ) A.﹣5 

二次不等式ax2+bx+10的解集为{x|1x},则ab的值为(  )

A.﹣5  B5    C.﹣6  D6

答案

D

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