已知:如图,在△ABC、△ADE中,∠BAC=∠DAE=90°,AB=AC,AD=AE,点

已知:如图,在ABCADE中,∠BACDAE90°ABACADAE,点CDE三点在同一直线上,连结BD.

求证:(1)BAD≌△CAE 

(2)试猜想BDCE有何特殊位置关系,并证明.

答案

1ABAC,易证∠BAD=∠CAE ADAE,所以△BAD≌△CAESAS)。

2BDCE证明略。

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