将Na在空气中加热一段时间，将产物投入水中，收集产生的气体于密

将Na在空气中加热一段时间，将产物投入水中，收集产生的气体于密闭容器中引燃，恰好完全反应。向所得的溶液中加入100g质量分数为36.5%的HCl，恰好呈中性。

（1）原来Na的质量为多少克？（已知：2Na2O2+2H2O==4NaOH+O2↑）

（2）求加热后产物中剩余的Na与Na2O2的质量比。

答案

解：（1）最终溶质为NaCl

NaOH～ HCl ～ NaCl ～ Na

36.5g 23g

36.5%×100g m(Na) ∴m(Na)=23g (3分)

（2）2Na～H2 2Na2O2～ O2

又2H2～ O2故4Na ～ 2Na2O2∴　

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