如图所示,用两根绳子把重10 kg的物体W吊在水平杆子AB上,∠ACW=150°,

如图所示,用两根绳子把重10 kg的物体W吊在水平杆子AB上,∠ACW=150°,∠BCW=120°,则A和B处所受力的大小(绳子的重量忽略不计)分别是___________.

答案

思路分析:

如图作平行四边形ODEF.使∠DOE=60°、∠EOF=30°.则G1、G2分别是重物分解到B处和A处的力.

||=|G

|cos60°=10×=5(kg),||=|G|cos30°=10×(kg),

∴在A处,B处所受的力的大小分别是kg、5 kg.

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