某人用单摆测定山顶高度(海拔高度),在山顶用标准计时装置记录

某人用单摆测定山顶高度(海拔高度),在山顶用标准计时装置记录单摆(等幅振动)振动1 000次的时间.再将该单摆移到海拔高度为零、g=9.8 m/s2的低处,在同一时间内,单摆振动了1 001次.地球半径R取6 400 km,求此山的海拔高度.

答案

6.4 km


解析:

根据题意可知周期之比为=,根据公式T=2π可得:c=()2=()2.又因为G=mg0,G=mg,所以()2==()2,解得h=R/1 000=6.4 km.

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