某有机物A质谱图、核磁共振氢谱图如下,则A的结构简式可能为( ) A

某有机物A质谱图、核磁共振氢谱图如下,则A的结构简式可能为(  )

A. HCOOH               B. CH3CHO               C. CH3CH2OH             D. CH3CH2CH2COOH

答案

【答案】C

【解析】

【详解】根据质谱图可知其相对分子质量为46,选项中只有HCOOH和CH3CH2OH的相对分子质量为46,而HCOOH只有两种等效氢,CH3CH2OH有三种等效氢,且三种氢原子的数值比为3:2:1,符合核磁共振氢谱图,故答案为C。

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