过氧化氢溶液在二氧化锰的条件下能迅速分解成氧气和水。分液漏斗

过氧化氢溶液在二氧化锰的条件下能迅速分解成氧气和水。分液漏斗可以通过调节活塞控制液体滴加速度。回答下列问题:

(1)分液漏斗中应放入的物质是        ,锥形瓶中应放入的物质是         

(2)要收集一瓶纯净的氧气应选择上图中的装置            (填字母)。

(3)某同学在观察到锥形瓶内有大量气泡时,开始用C装置收集氧气, 过一断时间后用带火星的木条伸入瓶口、瓶中、瓶底,都未见木条复燃。其可能原因是                 

(4)为检验装置B中氧气是否收集满,可用带火星的木条放在集气瓶的______,这是利用了氧气           的性质。

(5)若实验时用此法代替高锰酸钾加热制氧气,优点是        (填序号)

A.生成物中只有氧气      B.不需加热            C.需加热

(6)装置A中反应剧烈,据此提出实验安全注意事项是      

A.控制液体的滴加速度    B.用体积小的锥形瓶        C.加热反应物

答案

1)过氧化氢溶液   二氧化锰    23)装置漏气 (其他合理答案均可)

4)瓶口    支持燃烧  56A

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